Greedy / Lazy Quantifiers
Regular Expressions: Greedy / Lazy Quantifiers
What is a lazy quantifier in regex?
View Answer:
Here is an example of using lazy and greedy quantifiers in JavaScript:
let str = '<div>hello</div><div>world</div>';
// greedy
let greedyResult = str.match(/<div>.*<\/div>/)[0];
console.log(greedyResult); // '<div>hello</div><div>world</div>'
// lazy
let lazyResult = str.match(/<div>.*?<\/div>/)[0];
console.log(lazyResult); // '<div>hello</div>'
In the greedy example, the '.∗' matches as much as it can, including the closing '</div>' of the first div and the opening '<div>' of the second. In contrast, the lazy '.∗?' in the second example stops matching as soon as it encounters the first '</div>'.
Can you explain the difference between greedy and lazy quantifiers?
View Answer:
The notion of greedy/lazy quantifiers only exists in backtracking regex engines. In non-backtracking regex engines or POSIX-compliant regex engines, quantifiers only specify the repetition's upper and lower bound without specifying how to find the match.
// Greedy Quantifier
let regexp = /".+"/g;
let str = 'a "witch" and her "broom" is one';
console.log(str.match(regexp)); // "witch" and her "broom"
// Lazy Quantifier
let regexp = /".+?"/g;
let str = 'a "witch" and her "broom" is one';
console.log(str.match(regexp)); // "witch", "broom"
How do you make a greedy quantifier lazy?
View Answer:
Sure, here is a JavaScript code example illustrating the difference between greedy and lazy quantifiers:
let str = '1234567890';
// greedy
let greedyResult = str.match(/\d{3,}/)[0];
console.log(greedyResult); // '1234567890'
// lazy
let lazyResult = str.match(/\d{3,}?/)[0];
console.log(lazyResult); // '123'
In the greedy example, '\d{3,}' matches as many digit characters as possible (3 or more), so it returns the entire string. In contrast, the lazy '\d{3,}?' returns as soon as it finds the minimum number of matches (3 digits).
What are the effects of a lazy quantifier on regex performance?
View Answer:
How does a greedy quantifier behave when there's a match conflict?
View Answer:
Let's look at an example where a greedy quantifier might cause a conflict.
Suppose we have the text:
let text = "The rain in Spain";
And we want to match anything between "The" and "Spain". A simple and naive regex to do this might be:
let regex = /The.*Spain/;
The "." is a greedy quantifier - it matches any character (.) any number of times (). The problem here is that the greedy quantifier tries to match as many characters as possible, causing it to consume more of the string than you might expect. If you use this regex on our text, it will match the whole string "The rain in Spain".
That's because the greedy quantifier ".*" matches as much of the string as possible while still allowing the regex to match. It will include the " in " part because it can. This is what is meant by a "match conflict" - you wanted to match only up to the first space, but the greedy quantifier went further because it could.
You could use a lazy quantifier to resolve this. A lazy quantifier will match as few characters as possible:
let regex = /The.*?Spain/;
This will match "The rain in Spain" - the shortest possible string that still matches the pattern. This is how you can resolve conflicts with a greedy quantifier: by making it lazy instead.
It's worth noting that regular expressions can become quite complex and sometimes counterintuitive, particularly when you start adding in more advanced features like lookaheads and lookbehinds. The key to understanding them is to remember that they always try to find a match, and the different quantifiers and modifiers change how they go about finding that match.
In what scenario would you prefer a lazy quantifier over a greedy one?
View Answer:
How does a lazy quantifier behave when there's a match conflict?
View Answer:
Let's consider an example.
Assume we have the following text:
let text = "<div>Content1</div><div>Content2</div>";
We want to extract the content within each <div>
tag. A naive regex for this might look like:
let regex = /<div>(.*)<\/div>/;
In this regex, (.*)
is a greedy quantifier. It will match as much as possible. So, when used with the text
string, it will match everything from the first <div>
to the last </div>
, giving us "Content1</div><div>Content2".
This is a match conflict because it captures more than we intended. The conflict arises due to the greedy nature of the (.*)
quantifier.
We can fix this by making the quantifier lazy, i.e., making it match as few characters as possible:
let regex = /<div>(.*?)<\/div>/;
Here, (.*?)
is a lazy quantifier. It will match as few characters as possible. Now, when we use this regex with our text
, it will match "Content1" and "Content2" separately, which is what we intended.
How does the "{n,}?" quantifier function in regex?
View Answer:
Let's take a look at an example.
Suppose we have the following string:
let str = "1111222233334444";
And we want to match at least 2 occurrences of the number 1
, but as few as possible.
We can write our regular expression as:
let regex = /1{2,}?/;
When used with our str
string, it will match the first two 1
s, and stop, because it satisfied the minimum (2 occurrences) and is trying to match as few as possible due to the ?
.
The {n,}?
quantifier is particularly useful in cases where you want to ensure a minimum number of matches, but don't want the regex to be too greedy and overmatch.