Quantifiers
Regular Expressions: Quantifiers
What is a quantifier in JavaScript Regex?
View Answer:
// Sequence of digits
console.log("I'm 12345 years old".match(/\d{5}/)); // "12345"
// Range of digits
console.log("I'm not 12, but 1234 years old".match(/\d{3,5}/)); // "1234"
// Omitting the upper range with \d{3,}
console.log("I'm not 12, but 345678 years old".match(/\d{3,}/)); // "345678"
// Implementation on a range and omitting the upper range
let str = '+7(903)-123-45-67';
let numbers = str.match(/\d{1,}/g);
console.log(numbers); // 7,903,123,45,67
What does the '*' quantifier mean in Regex?
View Answer:
const regex = /ab*c/;
const strings = ['ac', 'bc', 'abc', 'abbbc', 'adc'];
for (const str of strings) {
if (regex.test(str)) {
console.log(`Match found: ${str}`);
} else {
console.log(`No match found: ${str}`);
}
}
Output:
"Match found: ac"
"No match found: bc"
"Match found: abc"
"Match found: abbbc"
"No match found: adc"
What does the '+' quantifier do in JavaScript Regex?
View Answer:
const regex = /ab+c/;
const strings = ['ac', 'abc', 'abbbc', 'adc'];
for (const str of strings) {
if (regex.test(str)) {
console.log(`Match found: ${str}`);
} else {
console.log(`No match found: ${str}`);
}
}
Output:
"No match found: ac"
"Match found: abc"
"Match found: abbbc"
"No match found: adc"
This demonstrates how the '+' quantifier behaves in JavaScript regex.
What does the '?' quantifier mean in Regex?
View Answer:
JavaScript
const regex = /ab?c/;
const strings = ['ac', 'abc', 'abbc', 'adc'];
for (const str of strings) {
if (regex.test(str)) {
console.log(`Match found: ${str}`);
} else {
console.log(`No match found: ${str}`);
}
}
When you run this code, you will see the following output:
Match found: ac
Match found: abc
No match found: abbc
No match found: adc
What does the {n,} quantifier mean in Regex?
View Answer:
JavaScript:
const regex = /a{2,}b/;
const strings = ['ab', 'aab', 'aaab', 'aaaaab', 'ac'];
for (const str of strings) {
if (regex.test(str)) {
console.log(`Match found: ${str}`);
} else {
console.log(`No match found: ${str}`);
}
}
When you run this code, you will see the following output:
No match found: ab
Match found: aab
Match found: aaab
Match found: aaaaab
No match found: ac
What does the {n,m} quantifier mean in Regex?
View Answer:
JavaScript:
const regex = /a{2,4}b/;
const strings = ['ab', 'aab', 'aaab', 'aaaab', 'aaaaab', 'ac'];
for (const str of strings) {
if (regex.test(str)) {
console.log(`Match found: ${str}`);
} else {
console.log(`No match found: ${str}`);
}
}
When you run this code, you will see the following output:
No match found: ab
Match found: aab
Match found: aaab
Match found: aaaab
No match found: aaaaab
No match found: ac
This demonstrates how the {n,m}
quantifier behaves in JavaScript regex by specifying a range for the number of occurrences of the preceding element.
Can quantifiers be used with groups in Regex?
View Answer:
let regex = /(abc)+/;
let string1 = 'abcabc';
let string2 = 'abca';
console.log(regex.test(string1)); // Outputs: true
console.log(regex.test(string2)); // Outputs: false
Remember that when you use quantifiers on groups, the entire group is affected, not just the last element in the group.
What is the difference between greedy and lazy quantifiers in Regex?
View Answer:
let greedyRegex = /a.*b/;
let lazyRegex = /a.*?b/;
let string = 'acbdb';
console.log(string.match(greedyRegex)[0]); // Outputs: 'acbdb'
console.log(string.match(lazyRegex)[0]); // Outputs: 'acb'
In this example, the first regular expression a.*b
is greedy. When it is used to match the string 'acbdb'
, it matches the entire string because the .*
quantifier consumes as many characters as possible.
The second regular expression a.*?b
is lazy because of the ?
after .*
. When this regex is used to match the string 'acbdb'
, it matches the shortest possible string that starts with 'a'
and ends with 'b'
, which is 'acb'
.
What is the difference between '+' and '* ' quantifiers in Regex?
View Answer:
let regexPlus = /a+/;
console.log(regexPlus.test('bbbb')); // Outputs: false
console.log(regexPlus.test('baaab')); // Outputs: true
let regexStar = /a*/;
console.log(regexStar.test('bbbb')); // Outputs: true, as * matches zero occurrences as well
console.log(regexStar.test('baaab')); // Outputs: true
In the example above, a+
does not match 'bbbb' as there is no 'a' in it, while a*
matches 'bbbb' as zero 'a' is also considered a match. Both a+
and a*
match 'baaab' because it contains one or more 'a'.
Can we use quantifiers with character classes in Regex?
View Answer:
let regex = /[a-z]+/; // This will match one or more lowercase letters
let testString = "Hello World 123";
console.log(testString.match(regex)); // Outputs: ["ello"]
let regexDigits = /\d{2,4}/; // This will match between 2 and 4 digits
let testDigits = "1234 5678 90";
console.log(testDigits.match(regexDigits)); // Outputs: ["1234"]
In the first example, [a-z]+
matches one or more lowercase letters in a row. In the test string "Hello World 123", it matches "ello", which is the first sequence of one or more lowercase letters.
In the second example, \d{2,4}
matches between 2 and 4 digits in a row. In the test string "1234 5678 90", it matches "1234", which is the first sequence of between 2 and 4 digits.
How do you represent 'n' or more occurrences in Regex?
View Answer:
Here is an example where we want to match 2 or more occurrences of the character 'a'.
let regex = /a{2,}/;
console.log(regex.test('a')); // Outputs: false
console.log(regex.test('aa')); // Outputs: true
console.log(regex.test('aaa')); // Outputs: true
In the example above, 'a' is not a match because there is only one 'a'. However, 'aa' and 'aaa' are matches because they contain at least two 'a' characters.
You can also apply this to groups:
let regex = /(abc){2,}/;
console.log(regex.test('abc')); // Outputs: false
console.log(regex.test('abcabc')); // Outputs: true
console.log(regex.test('abcabcabc')); // Outputs: true
In this case, 'abc' is not a match because it appears only once. However, 'abcabc' and 'abcabcabc' are matches because they contain at least two occurrences of 'abc'.
How does a non-greedy quantifier work in Regex?
View Answer:
let greedyRegex = /a.*b/;
let lazyRegex = /a.*?b/;
let str = 'acbcb';
console.log(str.match(greedyRegex)[0]); // Outputs: 'acbcb'
console.log(str.match(lazyRegex)[0]); // Outputs: 'acb'
In this example:
- The greedy regular expression
a.*b
matches as many characters as possible between 'a' and 'b', so it matches the entire string 'acbcb'. - The lazy regular expression
a.*?b
matches as few characters as possible between 'a' and 'b', so it only matches 'acb'. After finding the first 'b', it stops matching, even though there's another 'b' later in the string.
So, a non-greedy quantifier tries to find the smallest match. This can be very useful when you want to find multiple separate matches in a string, rather than a single combined match.
How do you match exactly 'n' times of a certain character?
View Answer:
let regex = /a{3}/;
console.log(regex.test('aa')); // Outputs: false
console.log(regex.test('aaa')); // Outputs: true
console.log(regex.test('aaaa')); // Outputs: true
In the example above, 'aa' is not a match because there are only two 'a' characters. However, 'aaa' and 'aaaa' are matches because they contain at least three 'a' characters. Note that in 'aaaa', it matches the first three 'a' characters and the fourth 'a' is not considered in the match.
You can also apply this to groups:
let regex = /(abc){3}/;
console.log(regex.test('abcabc')); // Outputs: false
console.log(regex.test('abcabcabc')); // Outputs: true
console.log(regex.test('abcabcabcabc')); // Outputs: true
In this case, 'abcabc' is not a match because 'abc' appears only twice. However, 'abcabcabc' and 'abcabcabcabc' are matches because they contain at least three occurrences of 'abc'. Note that in 'abcabcabcabc', it matches the first three 'abc' sequences and the fourth 'abc' is not considered in the match.
Can you match a certain range of repetitions with Regex?
View Answer:
Here's a JavaScript code example demonstrating the use of regex with the '{min,max}' quantifier to match a certain range of repetitions:
const regex = /a{2,4}/;
const testString = "aa, aaa, aaaa, aaaaa";
const matches = testString.match(regex);
console.log(matches); // Output: ["aa", "aaa", "aaaa"]
In this example, the regex pattern /a{2,4}/
will match the letter 'a' repeated between 2 to 4 times. The match()
method is used to find all matches in the testString
and return them as an array. The resulting matches are then printed to the console.
Is it possible to use quantifiers with special characters in Regex?
View Answer:
Here are some examples:
Match one or more digits:
let regex = /\d+/;
console.log(regex.test('123')); // Outputs: true
console.log(regex.test('abc')); // Outputs: falseMatch zero or more whitespace characters:
let regex = /\s*/;
console.log(regex.test(' ')); // Outputs: true
console.log(regex.test('abc')); // Outputs: trueMatch exactly 3 word characters (letters, digits, or underscores):
let regex = /\w{3}/;
console.log(regex.test('abc')); // Outputs: true
console.log(regex.test('ab')); // Outputs: false
Remember that if you want to use a character that is usually a special character in regex (like ., \, +, *, ?, ^, $, (, ), [, ], {, }, |, /) as a normal character to match in the string, you have to escape it using a backslash \
.
For example, to match exactly three dollar signs, you would use /\$\$\$/
.
How can you make a character optional in Regex?
View Answer:
let regex = /ab?c/;
console.log(regex.test('ac')); // Outputs: true
console.log(regex.test('abc')); // Outputs: true
console.log(regex.test('abbc')); // Outputs: false
In the example above, the 'b' character is optional. The regular expression ab?c
will match either 'ac' or 'abc', but not 'abbc' because it has two 'b' characters.
You can also make groups optional by placing the ?
after the group. For example:
let regex = /(abc)?def/;
console.log(regex.test('def')); // Outputs: true
console.log(regex.test('abcdef')); // Outputs: true
console.log(regex.test('abcabc')); // Outputs: false
In this example, the group 'abc' is optional. The regular expression (abc)?def
will match either 'def' or 'abcdef', but not 'abcabc' because it doesn't contain 'def'.
How do you make a quantifier lazy in Regex?
View Answer:
Here's an example using the lazy *?
quantifier...
let regex = /a.*?b/;
console.log(regex.exec('acbdb')); // Outputs: ["acb"]
In the example above, a.*?b
matches as few characters as possible between 'a' and 'b'. So it matches 'acb' in the string 'acbdb'.
You can also use +?
, ??
, or {n,m}?
to create lazy versions of the +
, ?
, and {n,m}
quantifiers, respectively. For example:
let regex = /a.+?b/;
console.log(regex.exec('acbdb')); // Outputs: ["acb"]
In this example, a.+?b
matches one or more characters as few as possible between 'a' and 'b'. So it matches 'acb' in the string 'acbdb'.
Are there any shorthand alias quantifiers in regular expressions?
View Answer:
let str = '+7(903)-123-45-67';
console.log(str.match(/\d+/g)); // 7,903,123,45,67
let str = 'Should I write color or colour?';
console.log(str.match(/colou?r/g)); // color, colour
console.log('100 10 1'.match(/\d0*/g)); // 100, 10, 1
console.log('100 10 1'.match(/\d0+/g)); // 100, 10
// 1 not matched, as 0+ requires at least one zero